(1/9) sqrt 3 * sqrt 27 ?
note 27 = 3^3 so sqrt 27 = 3^1.5
3^-2 * 3^.5 * 3^(1.5)
= 3^-2 * 3^+2
= 3^0 = 1
Solve and show workings
3√/9 *27√
It's supose to be the square root of 3 over 9 time the quare root of 27.
i know the answer is 1 however i don't know how to get that answer. Any help would be appriciated. Thanks
2 answers
thankyou so much!
3 answers