To solve the equation \(2(5 - 3x) = 3(2x + 1)\), let's start by expanding both sides.
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Distribute on the left side: \[ 2(5 - 3x) = 10 - 6x \]
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Distribute on the right side: \[ 3(2x + 1) = 6x + 3 \]
Now the equation becomes: \[ 10 - 6x = 6x + 3 \]
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Next, let's move all terms involving \(x\) to one side and constant terms to the other side. Start by adding \(6x\) to both sides: \[ 10 = 12x + 3 \]
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Now, subtract \(3\) from both sides: \[ 7 = 12x \]
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Finally, divide by \(12\): \[ x = \frac{7}{12} \]
Now that we have the solution \(x = \frac{7}{12}\), let's check it by substituting it back into the original equation.
Original equation: \[ 2(5 - 3x) = 3(2x + 1) \] Substituting \(x = \frac{7}{12}\):
Calculate the left side: \[ 2(5 - 3 \cdot \frac{7}{12}) = 2(5 - \frac{21}{12}) = 2(5 - 1.75) = 2(3.25) = 6.5 \]
Calculate the right side: \[ 3(2 \cdot \frac{7}{12} + 1) = 3(\frac{14}{12} + 1) = 3(\frac{14}{12} + \frac{12}{12}) = 3(\frac{26}{12}) = 3 \cdot \frac{13}{6} = \frac{39}{6} = 6.5 \]
Both sides are equal, so the solution is verified.
Hence, the correct choice is: A. The solution set is \({ \frac{7}{12} }\).