Solve an equilibrium problem (using an ICE table) to calculate the of each of the following solutions.

Question

.16M CH3NH3Cl

Answer 1

Your post is incomplete. You don't specify what you want calculated.
....CH3NH3^+ + H2O ==> H3O^+ + CH3NH2
I....0.16................0........0
C.......-x.............. x........x
E....0.16-x..............x........x

Ka(for CH3NH3Cl) = [Kw/Kb for CH3NH2)] = (x)(x)/(0.16-x) and solve for x = (H3O^+) and convert to pH if needed.