L = 3W-2
L*W = 65
(3W-2)W = 65
3W^2 - 2W - 65 = 0
Factor to solve for W, then insert W value in the first equation to find L.
Solve algebraically using only variable: The length of a rectangle is two less than three times
its width. If the area of the rectangle is 65, find the length and the width. (The area of a rectangle is equal to its length times its width.
1 answer
1 answer