Solve algebraically using one variable: Find three consecutive odd integers such that the

Question

product of the first integer and the third integer is equal to nine more than twelve times the middle integer.

Answer 1

Let the first integer be x-2, then middle integer is x and the third is x+2.

(x-2)(x+2) = 12x + 9

X^2 - 4 = 12x + 9

x^2 - 12x - 13 = 0

(x+1)(x-13) = 0

11 * 15 = 12*13 + 9