Solve ABC if C=90 degrees, B=20 degrees, and b=10. Round measures of side to the nearest tenth and measures of angles to the nearest degree.

Question

So all I need to do for this problem is find A,a,c right? I know that A=70 b/c 90+20=110 and 180-110=70 but how do I find a,c?

Answer 1

You have a right-angled triangle, so basic trig can be used.

tan20º = 10/a and sin20º = 10/c, so
a = 10/tan20 and c=10/sin20