solve 6x + 64 = 90 and 6x - 72 = 180

Answer 1

Let's solve the equations one by one.

1. For the equation \(6x + 64 = 90\):

   \[ 6x + 64 = 90 \]

   Subtract 64 from both sides:

   \[ 6x = 90 - 64 \] \[ 6x = 26 \]

   Now divide by 6:

   \[ x = \frac{26}{6} = \frac{13}{3} \approx 4.33 \]

2. For the equation \(6x - 72 = 180\):

   \[ 6x - 72 = 180 \]

   Add 72 to both sides:

   \[ 6x = 180 + 72 \] \[ 6x = 252 \]

   Now divide by 6:

   \[ x = \frac{252}{6} = 42 \]

So the solutions are:

• For the first equation, \(x = \frac{13}{3} \approx 4.33\)
• For the second equation, \(x = 42\)