There are different methods to solve this problem, but one common way is to use the formula for combinations:
nCr = n! / r!(n-r)!
where n is the total number of items, r is the number of items to choose, and (!) denotes the factorial function, which means the product of all positive integers up to that number.
For 6C3, we have:
n = 6 and r = 3
So the formula becomes:
6C3 = 6! / 3!(6-3)! = 6 x 5 x 4 / 3 x 2 x 1 = 20
Therefore, there are 20 ways to choose 3 items out of 6, assuming that order does not matter and repeats are not allowed.
Solve:
6C3
1 answer