Solving implies that you are dealing with an equation.
You did not give an equation.
SOLVE:
(3x-5)^3
that's to the third power
4 answers
sorry ...it is cubing binomials and the avove problem
What is it equal to??
You still did not state the "equation"
It should look something like
(3x-5)^3 = ????
are you just expanding (3x+5)^3
you could do it the long way by doing
(3x+5)(3x+5)(3x+5)
or you could use Pascal's triangle whose third row has coefficients 1 3 3 1
so
(3x+5)
= 1(3x)^3 + 3(3x^2)(5) + 3(3x)(5^2) + 5^3
= 27x^3 + 135x^2 + 225x + 125
You still did not state the "equation"
It should look something like
(3x-5)^3 = ????
are you just expanding (3x+5)^3
you could do it the long way by doing
(3x+5)(3x+5)(3x+5)
or you could use Pascal's triangle whose third row has coefficients 1 3 3 1
so
(3x+5)
= 1(3x)^3 + 3(3x^2)(5) + 3(3x)(5^2) + 5^3
= 27x^3 + 135x^2 + 225x + 125
great!!! thanks so much ...... you are a life saver!!!!! =)
1 answer