Question

solve 2z^2=5z+3 by factoring. I'm supposed to use ax^2+bx+c=0, but I don't know hot to make it so that they're all on one side and still aren't negatives. Please help.

Answer 1

2z^2 -5z -3 = 0
(2z +1)(z -3) = 0
z = -1/2 or z = 3

Answer 2

2z^2 = 5z + 3
Move them all to one side by subtracting 5z + 3 from both sides.

2z^2 - 5z - 3 = 0

I think I understand why you are confused. ax^2+bx+c = 0 is the general form of a quadratic equation.

In this case..
a = 2
b = -5
c = -3

Substitute the values into the general quadratic equation.

2x^2 + (-5)x + (-3) = 0
which is the same as
2x^2 - 5x - 3 = 0
You can change x to z.
2z^2 - 5x - 3 = 0

Now, factor it.

Answer 3

thanks! :D