2x^2 + 7x + 8 = 0
B^2 = 7^2 = 49
4AC = 4*2*8 = 64.
Since B^2 is less than 4AC, there are
no real solution. But there are 2 imaginary solutions:
X = (-B +-sqrt(B^2-4AC))/2A
X =(-7 +-sqrt(49-64))/4
X = (-7+-sqrt(-15))/4
X = (-7+-sqrt(15*-1))/4
X = (-7+-(3.87i))/4
X = -1.75 + 0.968i, and -1.75 - 0.968i.
For 2 real solutions: B^2 => 4AC
Solve 2x^2 + 7x = -8 using the Quadratic Formula.
A: No solution?
1 answer