Solve 2x^2-12+4=0 by completing the square, expressing the result in simplest radical form.

Answer 1

I will asssume you have a typo and meant
2x^2-12x+4=0
divide each term by 2
x^2 - 6x = -2
add 9 to both sides
x^2 - 6x + 9 = -2 + 9
(x-3)^2 = 7
take √ root of both sides
x - 3 = ± √7
x = 3 ± √7

Answer 2

yes, thank you for the help