Solve 2x + 10 greater then are equal to 12 Make sure to write your inequality so that x comes first

Answer 1

To solve the inequality \( 2x + 10 \geq 12 \), follow these steps:

1. Subtract 10 from both sides:

   \[ 2x + 10 - 10 \geq 12 - 10 \]

   This simplifies to:

   \[ 2x \geq 2 \]

2. Divide both sides by 2:

   \[ \frac{2x}{2} \geq \frac{2}{2} \]

   This simplifies to:

   \[ x \geq 1 \]

Now, to write the inequality so that \( x \) comes first, you can rearrange it:

\[ x \geq 1 \]

This can also be written as:

\[ 1 \leq x \]

Thus, the final inequality is:

\[ x \geq 1 \]

or equivalently,

\[ 1 \leq x \]