Question

Solve -1000+y^3, where y is a real number

Simplify your answer as much as possible.
If there is more than one solution, separate them with commas.

Answer 1

ty

Answer 2

what do you mean by "solve"?
It can be factored as the difference of two cubes:
(y-10)(y^2+10y+100)

If you want the solutions to
y^2-1000 = 0
then that is just y=10 or y=-5(1±√3 i)

Answer 3

y^3-1000