Solve -1000+y^3, where y is a real number
Simplify your answer as much as possible.
If there is more than one solution, separate them with commas.
3 answers
y^3-1000
ty
what do you mean by "solve"?
It can be factored as the difference of two cubes:
(y-10)(y^2+10y+100)
If you want the solutions to
y^2-1000 = 0
then that is just y=10 or y=-5(1±√3 i)
It can be factored as the difference of two cubes:
(y-10)(y^2+10y+100)
If you want the solutions to
y^2-1000 = 0
then that is just y=10 or y=-5(1±√3 i)
2 answers