To determine if the point (3, 8) is a solution to the simultaneous inequalities \(y > x + 5\) and \(y \leq 6x - 3\), we will substitute \(x = 3\) and \(y = 8\) into each inequality.
-
First Inequality: \(y > x + 5\)
Substituting the point (3, 8): \[ 8 > 3 + 5 \] \[ 8 > 8 \] This inequality is not satisfied because 8 is not greater than 8; it is equal.
-
Second Inequality: \(y \leq 6x - 3\)
Substituting the point (3, 8): \[ 8 \leq 6(3) - 3 \] \[ 8 \leq 18 - 3 \] \[ 8 \leq 15 \] This inequality is satisfied since 8 is less than or equal to 15.
Since the point (3, 8) does not satisfy the first inequality \(y > x + 5\), it is not in the solution set for this inequality, even though it is in the solution set for the second inequality \(y \leq 6x - 3\).
Therefore, the correct response is: No, it is in the solution set for \(y \leq 6x - 3\), but on the line for \(y > x + 5\).