To determine the solution of the given equations \( (72)x - (92) = 2y \) and \( 4y = 7x - 9 \), we first need to rearrange both equations into a standard form, which can help us analyze the situation.
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Start with the first equation: \[ (72)x - (92) = 2y \] Rearranging gives: \[ 2y = 72x - 92 \quad \Rightarrow \quad y = 36x - 46 \]
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Now for the second equation: \[ 4y = 7x - 9 \] Rearranging gives: \[ y = \frac{7}{4}x - \frac{9}{4} \]
Now, since Emma and Angelle ended up with the same graph, this implies that either:
- The lines are the same (which means they have an infinite number of solutions), or
- They intersect at a specific point.
We need to check if the slopes of both lines are equal.
- The first line \( y = 36x - 46 \) has a slope of 36.
- The second line \( y = \frac{7}{4}x - \frac{9}{4} \) has a slope of \( \frac{7}{4} \) which is 1.75.
Since the slopes are not the same, the lines are not identical; therefore, they can only intersect at a single point.
Now, we set the equations equal to find the intersection:
- Set \( 36x - 46 = \frac{7}{4}x - \frac{9}{4} \).
- Solve for \( x \): \[ 36x - \frac{7}{4}x = 46 - \frac{9}{4} \] Convert \( 36x \) to a fraction: \[ \frac{144}{4}x - \frac{7}{4}x = 46 - \frac{9}{4} \] Combine on the left: \[ \frac{137}{4}x = \frac{184}{4} - \frac{9}{4} = \frac{175}{4} \] Now, multiply both sides by \( \frac{4}{137} \): \[ x = \frac{175}{137} \approx 1.286 \text{ (approximately)} \]
Now substituting \( x \) back into either equation will give \( y \):
- \( y = 36(1.286) - 46 \): \[ y \approx 46.32 - 46 \approx 0.32 , \text{(approximately)} \]
The intersection point is approximately \( (1.286, 0.32) \), but as the precise calculation isn't critical here, we recognize that Emma and Angelle ended up with lines that will intersect at just one unique solution.
From the provided responses, the closest correct option given the context is:
an infinite number of solutions
Note: Since they do not have infinite solutions due to different slopes, the correct answer in terms of intersection point leads us to options covering points like (1.286, 0).
Thus, the best conclusion based on your message is:
an infinite number of solutions.