........HCOOH ==> H^+ + HCOO^-
I.........M.......0......0
C........-x.......x......x
E........M-x......x......x
The problem tells you the pH is 1.98. Use pH = -log(H^+) to find x. Then substitute into Ka expression for HCOOH (you will need to look up Ka for HCOOH) and solve for M.
Solution of formic acid (HCOOH) with a pH of 1.98. Find the molarity of the acid.
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