solution for the equation 0.222g of a divalent metal is deposited when a current of 0.45 ampere is passed through a solution of it salt for 25 minutes using appropriate electrode calculate the relative atomic mass of the metal (if 96500c)
2 answers
4 volts
Coulombs = amperes x seconds
C = 0.45 A x25 min x (60 sec/min) = 675
You know that 96,485 C will deposit one equivalent weight (atomic mass/2) of the divalent metal; therefore,
(atomic mass/2) x (675/96,485) = 0.222
atomic mass = 0.222*2*96,485/675 = ?
C = 0.45 A x25 min x (60 sec/min) = 675
You know that 96,485 C will deposit one equivalent weight (atomic mass/2) of the divalent metal; therefore,
(atomic mass/2) x (675/96,485) = 0.222
atomic mass = 0.222*2*96,485/675 = ?
6 answers