Solid titanium oxide (TiO2) reacts with solid carbon (C) to produce solid titanium (Ti) and gaseous carbon monoxide (CO). When 14.0 kg of C is allowed to react with 44.0 kg of TiO2 7.5 kg of Ti is produced. What is the theoretical yield of Ti expressed in mass and the percent yield?

Answer 1

TiO2 + 2C ==> 2CO + Ti
We don't need to make any corrections for molar mass and kg if we keep everything in kg.
kg mols C = 14.0/12 = approx 1.17
kg mols TiO2 = 44.0/79.88 = approx 0.5

Using the coefficients in the balanced equation, convert kg mols of each to kg mols of Ti.
for C that's 1 x (1 mol Ti/2 mol C) = approx 1.17 x 1/2 = approx 0.59 kg mol Ti from C.
for TiO2 that's 0.5 x (1 mol Ti/1 mol TiO2) = approx 0.5 kg mol Ti.
Note the values for Ti are different; in limiting reagent problems the smaller number is ALWAYS the correct value and the reagent producing that number is the limiting reagent. So we can obtain approx 0.5 kg mol Ti from the TiO2 reaction.
g TiO2 = mols x molar mass = ? kg Ti. This is the theoretical yield (100%).
The actual yield was 7.5kg.
%yield = (actual yield/theoretical yield)*100 = ?
Note I have used approximations. You need to redo all of the numbers.