sodium metal reacts violently with water to produce aqueous sodium hydroxide and hydrogen gas. calculate the enthalpy change for this reaction.

Answer 1

Write the equation and balance it.
Look up Hf for the products and reactants.
Then DHrxn = (n*DHfproducts) - (n*DHfreactants)

Answer 2

is it:
Na + H2O -> ????
Hf is hafnium.
i don't know this stuff.

Answer 3

2Na + H2O ==> H2 + 2NaOH
Hf is H_f = heat formation and hafnium is not involved with anything your are doing.
Look up the delta H_f values (they should be listed in your text as delta H^{o_f then
follow the equation I gave you. DHf stands for delta Ho_f.}

Answer 4

I made a typo trying to type the sub subscripts and superscripts.
.....should be listed in your text as delta H^o_f then follow......

Answer 5

i balanced the equation:
2 Na + 2 H2O = H2 + 2 NaOH.
What delta Hf value am i suppose to look up?