gotta work with moles.
286g CO2 * 1mole/44g = 6.5 moles CO2
Now recall the reaction:
Na2CO3 + 2HCl = 2NaCl + CO2 + H2O
Each mole of CO2 requires
1 mole Na2CO3
2 moles HCl
so, we need
6.5 moles Na2CO3 = 689g
13 moles HCl = 474g
sodium carbonate and hydrochloric acid react to give sodium chloride, carbon dioxide and water. How many grams of sodium carbonate and hydrochloric acid would be required to produce 286g of carbon dioxide?
step by step answers please:)
2 answers
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