Do you mean diborane? Not the usual method to make NaBH4!
2NaH + B2H6 -> 2NaBH4
work out the number of moles of each of the two starting materials so to find out if one is a limiting reagent. Then base your theoretical yield on the limiting reagent.
Once you have the theoretical yield then 0.868 x theoretical yield is the mass produced.
sodium borohydride (NaBH4) is used industrially in many organic syntheses. one way to prepare it is by reacting sodium hydride with gaseous diborone. Assuming an 86.8% yield,how many grams of NaBH4 can be prepared by reacting 7.98g of sodium hydride and 8.16g of diborone?
i tried 9.68 but it didn't work
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