so this problem tells me to find the thickness of one atomic layer of gold using the volume occupied by one gold atom (1.73*10^-23) which i found from the previous problem

Question

idk but is thickness the same as volume?
from the previous question it also gives me the density of gold metal- 18.9 g/cm^3

Answer 1

If it is spherical,assume the thickness is diameter

volume=4/3 PI (D/2)^3

(d/2)^3= 3*volume/(PI*4)

d/2=cubrt( )
d=2 cubrt(3Volume/(PI*4))

Answer 2

this is the right anwer

so

d= 3.21 x 10^(-10) m