so the question is:
the weights of fish in a certain lake are normally distributed with a mean of 10, a standard deviation of 6. if 4 fish are selected what is the probability that the mean weight will be between 7.6 and 13.6?
so usually to find prob, we use the normcdf function on the calculator, so it would be normcdf(7.6,13.6,10,6) but that doesn't work because you are selected 4 fish. that percent would be .38% for all the fish.
the correct answer is 67.30 percent but how do you get that?
2 answers
38% * not .38%
nevermind, i found a similar solution. :)
2 answers