If you drop an altitude to the center of the base, then looking from the side you have a right triangle with legs 4 and 22.
So, the hypotenuse of the triangle (the slant height of the pyramid, and the altitude of each triangular face) is
h = √(4^2+22^2) = √500 = 10√5
That means that the lateral area of the pyramid is that of the four faces, or
4 * (22 * 10√5)/2 = 440√5
So I've tried for two days to figure out this problem. I tried to ask my friend to help me but she just won't. My parents don't know anything about math, they said so themselves. The first day I tried I cried I got so frustrated. The second day I just gave up. Today is my last day before spring break. I have to show every step of my work, which is why it's so hard. I normally use calculators and I don't really know how exactly to figure this out.
Find the lateral area of the square pyramid.
Base 8m
Height 22m
Thank you so much~!
1 answer
3 answers