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So I'm trying to do my homework on L'Hopital's rule. There's this one problem I have to do where I have to find the limit as x approaches negative infinity of (x^4)(e^x). How do I do this, since it's not in the form f(x)/g(x)?

Thanks

2 answers

x^4*e^x = x^4/e^-x
use the Rule 4 times to get

24/e^-x = 24e^x --> 0
Oh I forgot I could use the rule more than once. Thanks!