Asked by Anthony

So im struggling in math right now and i need help to do this can anyone please explain step by step on how to do this its solving systems of equations by substitution
5x-4y=-23
y=1/3x-5
Answered by John
This is a complicated one for sure.
Let's get rid of the fraction in the second problem by multiplying by 3
3y =x - 15 next solve for 3y + 15 = x. I did this step so that I could use substitution to solve.

Back to the first equation: 5( x ) -4y = -23

I substitute here 5( 3y + 15) -4y = -23 use the distributive law to get
15y + 75 -4y = -23
11y + 75 = -23
11y = -98 Solve for y and then substitute back into one of the original equations to find x. Finally, check your answers for x and y in both equations.
Answered by Anthony
thank you this helped!
Answered by Reiny
5x-4y=-23
y=1/3x-5 ---> 3y = x - 15 or <b>x = 3y+15</b>

sub into the first
5(3y+15) - 4y = -23
15y + 75 - 4y = -23
11y = -98
y = -98/11
then x = 3(-98/11) + 15 = -129/11

John is right as well
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