y - 8 = x
x + y = 80
Substitute y-8 for x in the second equation and solve for y. Insert that value into the first equation to solve for x. Check by putting both values into the second equation.
So I solved this problem but, strange as it sounds, I don't know how to do the work.
Here's the question: One number is eight less than another number. The sum of the numbers is eighty. Find both numbers.
Here's what I've got:
y-8=x
x+y=80
x=36
y=44
I won't get credit unless I show the "correct" work. Can you help me please?
2 answers
y-8=x
x+y=80
Substitute
y - 8 + y = 80
2y = 88
y = 44
44 - 8 = x
36 = x
x+y=80
Substitute
y - 8 + y = 80
2y = 88
y = 44
44 - 8 = x
36 = x