I think I got it
6 mol A / 2 mol A x3 mol B = 9 mol B
So I have this question it reads
Consider the generic chemical reaction
How many moles of B are required to completely react with
2A + 3B ==> 3C
1. 6 mol of A
2. 2 mol of A
I won't put them all just guide me in the right direction please
3 answers
You're right. This is the same kind of problem I worked in detail last night for you with the limiting reagent problem. The dimensional approach lets you see that the old units cancel and the new unit remains.
6 moles A x (3 moles B/2 mols A) = 9 moles B. Note how the mols A term cancels and that factor I have in parentheses converts moles A to moles B using the coefficients in the balanced equation.
6 moles A x (3 moles B/2 mols A) = 9 moles B. Note how the mols A term cancels and that factor I have in parentheses converts moles A to moles B using the coefficients in the balanced equation.
help????