Asked by Anon

So I have the following differential equation.

The general solution I have is:

t=k(-1/r)+c

I now need to find the particular solution when t=0 and the radius (r) = 1cm.

So k is a constant which is approx 3.9 (5/4pi)

So for the particular solution im really just plugging in the numbers to find the value of c, is that correct?

Thanks

Answers

Answered by Anon
Just to add, by doing what I described above my answer for c would be the same value as for k (i.e 3.9 or 5/4pi) so my particular solution would be.

t=k(-1/r)+5/4pi

Answered by Steve
yes, c=k, so if k = 5π/4,

t = k (1 - 1/r)
= 5π/4 (1 - 1/r)
Answered by Anon
Thanks Steve.
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