Just to add, by doing what I described above my answer for c would be the same value as for k (i.e 3.9 or 5/4pi) so my particular solution would be.
t=k(-1/r)+5/4pi
So I have the following differential equation.
The general solution I have is:
t=k(-1/r)+c
I now need to find the particular solution when t=0 and the radius (r) = 1cm.
So k is a constant which is approx 3.9 (5/4pi)
So for the particular solution im really just plugging in the numbers to find the value of c, is that correct?
Thanks
3 answers
yes, c=k, so if k = 5π/4,
t = k (1 - 1/r)
= 5π/4 (1 - 1/r)
t = k (1 - 1/r)
= 5π/4 (1 - 1/r)
Thanks Steve.