So i am asked to write the equation representing the third ionization energy for Cr, and what I could come up with is Cr^2+(g)->Cr^3+ + e(not sure if I am right).

Question

For the second part I am told that the electron affinity of K is 48 kJ/mol, and i am supposed to write the equation for which this is the energy change, how would I approach this

Answer 1

a, right
b. K >> K+ + e^-

Answer 2

Do I not need to write Delta EA = 48 kj/mol