HCl(aq) + MnO2(s) →
2 H2O(l) + MnCl2(s) + Cl2(g).
mols MnO2 = grams/molar mass = ?
mols Cl2 produced = mols Cl2 produced since the reaction of 1 mol MnO2 produces 1 mol Cl2.
Then grams Cl2 = mols Cl2 x molar mass Cl2 = ?
Small amounts of chlorine gas can be gener- ated in the laboratory from the reaction of manganese(IV) oxide with hydrochloric acid: 4 HCl(aq) + MnO2(s) →
2 H2O(l) + MnCl2(s) + Cl2(g). What mass of Cl2 can be produced from 41.8 g
of MnO2 with an excess of HCl(aq)?
1 answer