Sloane kicked a soccer ball off the ground at a speed of 36 feet per second. The height of the ball can be represented by the function H(t) = −16t2 + 36t. How many seconds did the ball travel before returning to the ground?

t = 0.44 seconds
t = 2.25 seconds
t = 16 seconds
t = 36 seconds

3 answers

To find when the ball returns to the ground, we need to find when H(t) = 0. So we set the function equal to 0 and solve for t:

-16t^2 + 36t = 0

Factor out t:

t(-16t + 36) = 0

Either t = 0 or -16t + 36 = 0

Solving the second equation for t:

-16t + 36 = 0

-16t = -36

t = 2.25

So the ball traveled for 2.25 seconds before returning to the ground.

Answer: t = 2.25 seconds.
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