This is very late so for people who might need it at some point here's what I did:
The larger denominator is under y so the ellipse is going to be vertical.
Equation: (x-h)^2/b^2 + (y-k)^2/a^2 =1
The center is (0,0) right so both h and k will be 0
a is the length of the major axis
b is the length of the minor axis
x^2/50^2 + y^2/90^2 = 1
x^2/50^2 + y^2/90^2 = 1
a=90
90 x 2 is 180
The major axis' length is going to be 180 yards.
Skip designs tracks for amusement parks. For a new design the track will be ellipitical if the ellipse is placed on a large coordinate grid with its center at (0,0) the equation x^2/2500+y^2/8100=1 model the path of the park.The units are given in yards, how long is the major axis of the track?
Please help me
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thankfully this is also relevant 2023! Thanks Kiwi!
anyone realize this was asked in 2013?
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