a.=Wt. of skier=m*g=79kg9.8N/kg=774.2 N.
Fp = 774.2*sin30 = 387.1 N. = Force
parallel to the slope.
Work = F*d = 387.1 * 80 = 30,968 J.
b. Power=F*V = 387.1 * 3.4=1316 J./s.
= 1316 Watts.
1316W * 1hp/746W. = 1.76 hp.
skier of mass 79 kg is pulled up a slope by a motor-driven cable.
(a) How much work is required to pull him 80 m up a 30° slope (assumed frictionless) at a constant speed of 3.4 m/s?
1 J
(b) What power (expressed in hp) must a motor have to perform this task?
1 answer
1 answer