do you mean
4* integral dx/(2x+3)
or what?
Sketch the regions represented by the following integrals and evaluate them using geometric formulas.
4 integral 1: 2x+3dx
6 integral -2: lx-1l dx (absolute value of x-1
5 answers
4∫1 4 on the top and 1 on the bottom of that sign
6∫-2 same deal
6∫-2 same deal
Just use the power rule for these.
∫[1,4] 2x+3 dx = x^2+3x = 24
Recall the definition of |n|:
= n if n >= 0
= -n if n < 0
∫[-2,6] |x-1| dx has to be broken up at x=1, so you get
∫[-2,1] -(x-1) dx + ∫[1,6] (x+1) dx = 17
∫[1,4] 2x+3 dx = x^2+3x = 24
Recall the definition of |n|:
= n if n >= 0
= -n if n < 0
∫[-2,6] |x-1| dx has to be broken up at x=1, so you get
∫[-2,1] -(x-1) dx + ∫[1,6] (x+1) dx = 17
Thank you so much.
What would the sketched regions look like??
What would the sketched regions look like??
You're in calculus and can't sketch linear functions?
If you type in the integrals as I showed them, wolframalpha.com understands the notation. For example
http://www.wolframalpha.com/input/?i=%E2%88%AB%5B-2,6%5D+%7Cx-1%7C+dx
If you type in the integrals as I showed them, wolframalpha.com understands the notation. For example
http://www.wolframalpha.com/input/?i=%E2%88%AB%5B-2,6%5D+%7Cx-1%7C+dx