Asked by Leila
Sketch the regions represented by the following integrals and evaluate them using geometric formulas.
4 integral 1: 2x+3dx
6 integral -2: lx-1l dx (absolute value of x-1
4 integral 1: 2x+3dx
6 integral -2: lx-1l dx (absolute value of x-1
Answers
Answered by
Damon
do you mean
4* integral dx/(2x+3)
or what?
4* integral dx/(2x+3)
or what?
Answered by
Leila
4∫1 4 on the top and 1 on the bottom of that sign
6∫-2 same deal
6∫-2 same deal
Answered by
Steve
Just use the power rule for these.
∫[1,4] 2x+3 dx = x^2+3x = 24
Recall the definition of |n|:
= n if n >= 0
= -n if n < 0
∫[-2,6] |x-1| dx has to be broken up at x=1, so you get
∫[-2,1] -(x-1) dx + ∫[1,6] (x+1) dx = 17
∫[1,4] 2x+3 dx = x^2+3x = 24
Recall the definition of |n|:
= n if n >= 0
= -n if n < 0
∫[-2,6] |x-1| dx has to be broken up at x=1, so you get
∫[-2,1] -(x-1) dx + ∫[1,6] (x+1) dx = 17
Answered by
Leila
Thank you so much.
What would the sketched regions look like??
What would the sketched regions look like??
Answered by
Steve
You're in calculus and can't sketch linear functions?
If you type in the integrals as I showed them, wolframalpha.com understands the notation. For example
http://www.wolframalpha.com/input/?i=%E2%88%AB%5B-2,6%5D+%7Cx-1%7C+dx
If you type in the integrals as I showed them, wolframalpha.com understands the notation. For example
http://www.wolframalpha.com/input/?i=%E2%88%AB%5B-2,6%5D+%7Cx-1%7C+dx
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