Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region.
2y=4x^1/2,y=5,2y+1x=5
Do you really mean "2y+1x=5" ?
It is not customary to use the coefficient 1 in front of a variable. It is unnecessary.
Since y=5 is one boundary, it would be easiest to integrate from the lowest y value of the region to y=5.
The equation "2y=4x^1/2"
would be better written as y = 2x^1/2