Where do you get stuck?
The curve and the sloping line intersect at (1,5/2).
I'd integrate on y, from 5/2 to 5
5/2 sqrt(x) - (8-3x)/2
Sketch the region enclosed by 2y=5sqrtx, y=5 and 2y+3x=8.
Decide whether to integrate with respect to x or y, and then find the area of the region.
2 answers
Oops. Integrating on y we need x as f(y)
4y^2/25 - (8-2y)/3
4y^2/25 - (8-2y)/3