To analyze the piecewise function given:
\[ f(x) = \begin{cases} -6 & \text{if } x \geq -2 \ 6 & \text{if } x < -2 \end{cases} \]
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For \(x \geq -2\), \(f(x) = -6\). This means that there is a horizontal line at \(y = -6\) starting from \(x = -2\) and extending to the right. Since the inequality is inclusive, the point \((-2, -6)\) will be a closed point.
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For \(x < -2\), \(f(x) = 6\). This means there is another horizontal line at \(y = 6\) starting from \(x = -2\) and extending to the left. Since this part is exclusive, the point \((-2, 6)\) will be an open point.
Now let's examine each option:
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Option A:
- Closed point at \((-2, -6)\) moving right → Incorrect.
- Open point at \((-2, 6)\) moving left → Incorrect.
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Option B:
- Closed point at \((-2, 6)\) moving right → Correct.
- Open point at \((-2, -6)\) moving left → Incorrect.
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Option C:
- Closed point at \((-2, 6)\) moving left → Incorrect.
- Open point at \((-2, -6)\) moving right → Correct.
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Option D:
- Closed point at \((-2, 6)\) moving left → Incorrect.
- Open point at \((-2, -6)\) moving right → Correct.
None of the options perfectly match the description. However, the closest correct representation is Option B, which accurately shows the horizontal line at \(y = -6\) starting from \((-2, -6)\) moving to the right and the horizontal line at \(y = 6\) starting from \((-2, 6)\) moving to the left.
Therefore, the correct choice is Option B.