should be no problem. That's just Algebra II. Anyway,
y = x^3/(x+1)^2
y' = x^2(x+3)/(x+1)^3
y" = 6x/(x+1)^4
see the graph and some analysis here:
http://www.wolframalpha.com/input/?i=x^3%2F%28x%2B1%29^2
sketch the graph of the following. Show all your work and include all the important points and asymptotes.
also find y' and y'' ?
y= (x^3)/(x+1)^2
1 answer