Part 1:
The graph of the equation y = -x^2 + 4x - 4 is a downward opening parabola with vertex at (2,0).
Part 2:
The x-intercepts are found by setting y = 0:
0 = -x^2 + 4x - 4
x^2 - 4x + 4 = 0
(x - 2)^2 = 0
x - 2 = 0
x = 2
Therefore, the x-intercept is at (2,0).
Sketch the graph of the equation. Label the vertex and the intercepts.
yequalsminusxsquaredplus4xminus4
Question content area bottom left
Part 1
Use the graphing tool to graph the equation.
Part 2
The intercept(s) is/are
enter your response here.
(Type an ordered pair. Type an exact answer, using radicals as needed. Use a comma to separate answers as needed.)
1 answer