Here is a sketch of one cycle of the sine curve with the equation y = -3sin(4x):
The sine curve starts at the origin (0, 0), then reaches a peak at (π/2, -3), goes back to the x-axis at (π, 0), reaches the lowest point at (3π/2, 3), and finally returns to the origin at (2π, 0).
Sketch one cycle of the sine curve.
y = -3 sin 4o-
3 answers
no, the period is 2π/4 = π/2
That means it reaches a peak at (π/8,-3)
a zero at (π/4,0)
a peak at (3π/8,3)
a zero at (π/2,0)
That means it reaches a peak at (π/8,-3)
a zero at (π/4,0)
a peak at (3π/8,3)
a zero at (π/2,0)
Thank you for pointing that out. Here is the corrected sketch of one cycle of the sine curve with the equation y = -3sin(4x):
The sine curve starts at the origin (0, 0), reaches a peak at (π/8, -3), goes back to the x-axis at (π/4, 0), reaches another peak at (3π/8, 3), and returns to the x-axis at (π/2, 0).
The sine curve starts at the origin (0, 0), reaches a peak at (π/8, -3), goes back to the x-axis at (π/4, 0), reaches another peak at (3π/8, 3), and returns to the x-axis at (π/2, 0).