To solve for P(blue or medium), we will first identify the total number of items and how many of those items are blue and medium.
Breakdown of the data:
- Total items: 30 (total from the totals you provided)
Color Distribution:
- Yellow: 2 + 4 + 11 = 17 items
- Blue: 1 + 1 + 4 = 6 items
- Red: 1 + 2 + 4 = 7 items
The totals match: Yellow (17) + Blue (6) + Red (7) = 30.
Size Distribution:
From the information provided:
- Large: 4 items
- Medium: 7 items
- Small: 19 items
Finding "blue or medium":
Let's break it down into two parts:
- Total Blue items: 6
- Total Medium items: 7
Next, we need to check if there is any overlap between blue and medium items. Since the table with size breakdown does not explicitly show the intersection (how many of the blue items are medium), let's assume the worst-case scenario where there is no overlap:
- Blue: 6
- Medium: 7
Total = 6 + 7 = 13 (assuming no overlap).
P(blue or medium):
If there is no overlap, then: \[ P(blue , or , medium) = \frac{13}{30} \]
However, we should consider overlap. To be thorough, let's check if there is any overlap based on available counts.
Given the available data:
- Blue sizes are: 1, 1, 4 (which means the sizes of blue items are not specified).
- Without information on how many of these blue items can be medium, we consider them all as potential overlaps.
Hence, we'll use the result based on assumption and clear data.
- Since there is no explicit size allocation for blue items, we'll take our estimate of P(blue or medium) = 13/30 fits our conclusion.
The correct answer is:
D. 13/30.