Six years hence a man 's age will be three times his son 's age and three years ago,he was nine times as old as his son .find their present ages

Answer 1

6 years from now:
son's age ---- x
man's age --- 3x

present time: (subtract 6)
son's age --- x-6
man's age -- 3x-6

three years from now: (subtract 3)
son's age = x-9
man's age = 3x - 9

3x-9 = 9(x-9)
3x - 9 = 9x - 81
72 = 6x
x = 12

son's present age = 12-6 = 6 years
father's age = 36-6 = 30 years