To solve the equation: "six plus the quantity three minus x divided by two equals one"
1. Start by simplifying the expression inside the parentheses: "three minus x"
2. Distribute the division: "(three - x) / 2"
3. Substitute the simplified expression back into the equation: "six + (three - x) / 2 = 1"
4. Multiply both sides of the equation by 2 to eliminate the fraction: "2 * six + 2 * ((three - x) / 2) = 2 * 1"
Simplify: "12 + (three - x) = 2"
5. Combine like terms: "12 + three - x = 2"
Simplify: "15 - x = 2"
6. Subtract 15 from both sides of the equation: "15 - x - 15 = 2 - 15"
Simplify: "-x = -13"
7. Multiply both sides of the equation by -1 to isolate "x": "-1 * -x = -1 * -13"
Simplify: "x = 13"
Therefore, the solution to the equation is "x = 13".
six plus the quantity three minus x divided by two equals one
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