(Six pigpen problem). A 2 × 3 array of six congruent rectangular pigpens (that all look the same from above) will be in the overall shape of a rectangle R. We may use 100 feet of fencing to form the boundaries of the pigpens. Find the dimensions for a single pigpen that will maximize the total area of all the pigpens, and find this total area. (The fencing separating the pigpens has constant height, so we may ignore height in our calculations. Also, assume the boundaries between pigpens are not double - fenced; that is, assume that the thickness of the fencing between pigpens is the same as the thickness of the fencing along the outer boundary, R .)

My numbers are not coming at the same as my professor. I have redid this problem multiple times and I just cannot get it. Please explain.

1 answer

show what you did. This kind of problem always works out that the fencing is divided equally among lengths and widths. So, the entire array will have dimension

(50/3) by (50/4)

Each pen will be (50/9) by (50/8)

Start with

3x+4y = 100
a = xy = x*(100-3x)/4
then find x such that da/dx=0