6A = 4P
A = 4/6P = 1/3P
P = A + 4
Substitute P/3 for A in the third equation and solve for P.
Six apples cost as much as four pears. Each pear costs $4 more than each Apple. What is the cost of one pear?
3 answers
Or you could try it this way.
P-4 = A
6A = 4P
Substitute P-4 for A in the second equation and solve for P.
However, something seems askew here. Typos?
P-4 = A
6A = 4P
Substitute P-4 for A in the second equation and solve for P.
However, something seems askew here. Typos?
Each pear costs $4 more than each Apple ---
p = a + 4
Now , that's some expensive fruit !!
6a = 4p
6a = 4(a+4)
6a = 4a + 16
2a = 16
a = 8 , then p = 12
An apple costs $4 and a pear costs $12
WOW, but the answers check out for you info
p = a + 4
Now , that's some expensive fruit !!
6a = 4p
6a = 4(a+4)
6a = 4a + 16
2a = 16
a = 8 , then p = 12
An apple costs $4 and a pear costs $12
WOW, but the answers check out for you info