sinx+cosxcot=csc

1 answer

Generally, if you convert the trigonometric functions to sin and cos, it will make the solution more obvious.

sinx+cosxcot
=sin(x) + cos(x)*cos(x)/sin(x)
=(sinĀ²(x)+cosĀ²(x))/sin(x)

Can you take it from here?
Similar Questions
  1. Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
    1. answers icon 3 answers
    1. answers icon 3 answers
  2. Simplify sin x cos^2x-sinxHere's my book's explanation which I don't totally follow sin x cos^2x-sinx=sinx(cos^2x-1)
    1. answers icon 1 answer
  3. Hello! Can someone please check and see if I did this right? Thanks! :)Directions: Find the exact solutions of the equation in
    1. answers icon 1 answer
more similar questions