To find the day(s) on which the attendance was the same at both plays, we need to set the equations for Play A and Play B equal to each other and solve for x:
15x + 76 = -x^2 + 36x - 4
Rearranging the equation to set it equal to zero:
x^2 - 21x + 80 = 0
Factoring the quadratic equation:
(x - 5)(x - 16) = 0
Setting each factor to zero:
x - 5 =0 or x - 16 = 0
x = 5 or x = 16
Therefore, the attendance was the same on day 5 and day 16 at both plays. The attendance on those days was 151 and 316 respectively.
Since opening night, attendance at Play A has increased steadily, while attendance at Play B first rose and then fell. Equations modeling the daily attendance y at each play are shown below, where x is the number of days since opening night. On what day(s) was the attendance the same at both plays? What was the attendance? solve it and tell me why
Play A: y = 15x + 76
Play B: y = –x2 + 36x – 4
(1 point)
Responses
The attendance was the same on day 5. The attendance was 151 at both plays on that day.
The attendance was the same on day 5. The attendance was 151 at both plays on that day.
The attendance was the same on day 16. The attendance was 316 at both plays on that day.
The attendance was the same on day 16. The attendance was 316 at both plays on that day.
The attendance was the same on days 5 and 16. The attendance at both plays on those days was 151 and 316 respectively.
The attendance was the same on days 5 and 16. The attendance at both plays on those days was 151 and 316 respectively.
The attendance was never the same at both plays.
1 answer
1 answer