sinA+cosA=p and secA+CosecA=q

Question

then show that q[p^2-1]=2p

Answer 1

q[p^2-1]
= (secA + cosecA)[(sinA+cosA)^2 - 1]
= (secA + cosecA)[ (sin^2A + cos^2A) + 2sinAcosA - 1]
= (secA + cosecA)[ 1 + 2sinAcosA - 1 ]
= (secA + cosecA)(2sinAcosA)
= 2sinA + 2cosA
= 2(sinA + cosA) = 2p

Answer 2

Very good answer.THANKS

Answer 3

Thanks

Answer 4

show the steps in a better way